A) square planar, trigonal bipyramidal
B) T-shaped, octahedral
C) square pyramidal, octahedral
D) square planar, octahedral
Correct Answer: B
Solution :
[b] \[Xe{{F}_{4}}+Sb{{F}_{5}}\xrightarrow{{}}{{[Xe{{F}_{3}}]}^{+}}{{[Sb{{F}_{6}}]}^{-}}\xrightarrow{{}}\] \[\underset{\begin{smallmatrix} s{{p}^{3}}d \\ bent\,T-shape \end{smallmatrix}}{\mathop{{{[Xe{{F}_{3}}]}^{+}}}}\,+\underset{\begin{smallmatrix} s{{p}^{3}}d \\ octahedral \end{smallmatrix}}{\mathop{{{[Sb{{F}_{6}}]}^{-}}}}\,\]
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