A) it forms an explosive having the formula\[Xe{{O}_{2}}{{F}_{2}}\].
B) it forms an explosive having the formula\[XeO{{F}_{4}}\].
C) it forms \[Xe{{O}_{2}}\] which is explosive substance.
D) it forms \[Xe{{O}_{6}}^{4-}\] which is explosive in nature.
Correct Answer: B
Solution :
[b] \[2Xe{{F}_{6}}+\underset{glass}{\mathop{Si{{O}_{2}}}}\,\xrightarrow{{}}~\underset{(explosive\,nature)}{\mathop{2XeO{{F}_{4}}}}\,~+Si{{F}_{4}}\] \[2XeO{{F}_{4}}+Si{{O}_{2}}\xrightarrow{{}}2Xe{{O}_{2}}{{F}_{^{2}}}+Si{{F}_{4}}\] \[2Xe{{O}_{2}}{{F}_{2}}+Si{{O}_{2}}\xrightarrow{{}}2\underset{\exp losive}{\mathop{Xe{{O}_{3}}}}\,+Si{{F}_{4}}\]
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