A) sulphate ion
B) sulphite ion
C) tetrathionate ion
D) sulphide ion
Correct Answer: C
Solution :
[c] \[2N{{a}_{2}}{{S}_{2}}{{O}_{3}}+{{I}_{2}}\to \underset{\begin{smallmatrix} Sodium \\ tetrathionate \end{smallmatrix}}{\mathop{N{{a}_{2}}{{S}_{4}}{{O}_{6}}}}\,+2NaI\]
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