A) \[N{{a}_{2}}S{{O}_{3}}+HCl+S\]
B) \[N{{a}_{2}}S{{O}_{3}}+S{{O}_{3}}+HCl\]
C) \[N{{a}_{2}}S{{O}_{4}}+HCl+S\]
D) \[N{{a}_{2}}S{{O}_{4}}+HCl+S{{O}_{2}}\]
Correct Answer: C
Solution :
[c] \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}+C{{l}_{2}}+{{H}_{2}}O\xrightarrow{{}}\] \[2HCl+S+N{{a}_{2}}S{{O}_{4}}\]
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