A) reduced
B) oxidized
C) sulphonated
D) dehydrated
Correct Answer: D
Solution :
[d] \[{{C}_{12}}{{H}_{22}}{{O}_{11}}\xrightarrow[\Delta ]{{{H}_{2}}S{{O}_{4}}}\underset{black}{\mathop{12C}}\,+11{{H}_{2}}O\]
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