A) \[Cr{{O}_{4}}^{2-}\], basic medium
B) \[C{{r}_{2}}{{O}_{7}}^{2-}\], basic medium
C) \[C{{r}_{2}}{{O}_{7}}^{2-}\], acidic medium
D) \[Cr{{O}_{3}}\] basic medium
Correct Answer: C
Solution :
[c] \[CrO_{4}^{2-}(aq)+4{{H}_{2}}O+3{{e}^{-}}\xrightarrow{{}}\] \[Cr{{\left( OH \right)}_{3}}+5O{{H}^{-}},\] \[E{}^\circ =-0.13V\] \[C{{r}_{2}}O_{7}^{2-}(aq.)+14{{H}^{+}}(aq.)+6{{e}^{-}}\xrightarrow{{}}\] \[2C{{r}^{3+}}\left( aq. \right)+7{{H}_{2}}O,\] \[E{}^\circ =1.33V\]
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