A) one
B) two
C) three
D) four
Correct Answer: C
Solution :
[c] After absorbing 12.1 eV the electron in H atom is excited to 3 shell. \[{{E}_{n}}-{{E}_{1}}=\frac{-13.6}{{{n}^{2}}}-(-13.6)=12.1\] \[\frac{-13.6}{{{n}^{2}}}+13.6=12.1\] \[\therefore n=3\] The possible transitions are = 3
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