JEE Main & Advanced Chemistry Structure of Atom / परमाणु संरचना Question Bank Self Evaluation Test - Structure of Atom

  • question_answer
    The total spin and magnetic moment for the atom with atomic number 24 are:

    A) \[\pm 3,\sqrt{48}BM\]    

    B) \[\pm 3,\sqrt{35}BM\]

    C) \[\pm \frac{3}{2},\sqrt{48}BM\]   

    D) \[\pm \frac{3}{2},\sqrt{35}BM\]

    Correct Answer: A

    Solution :

    [a] Atomic number = 24 Electronic configuration is \[3{{d}^{5}},4{{s}^{1}}\] No. of valence \[{{e}^{-1}}(s)=6\] Total spin \[=\pm \frac{1}{2}\times 6=\pm 3\] Magnetic moment \[=\sqrt{n\left( n+2 \right)}=\sqrt{6\left( 6+2 \right)}\] \[=\sqrt{48}\,BM\]            


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