A) \[\frac{8R}{9}\]
B) \[\frac{32R}{9}\]
C) \[\frac{3R}{9}\]
D) None of these
Correct Answer: B
Solution :
[b] \[{{n}_{1}}+{{n}_{2}}=4;{{n}_{2}}-{{n}_{1}}=2;\,\,\,\,\therefore {{n}_{1}}=l,{{n}_{2}}=3\] \[\overline{v}=R{{(2)}^{2}}\left[ \frac{1}{{{1}^{2}}}-\frac{1}{{{3}^{2}}} \right]=\frac{32R}{9}\]
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