JEE Main & Advanced Chemistry Structure of Atom / परमाणु संरचना Question Bank Self Evaluation Test - Structure of Atom

  • question_answer
    According to law of photochemical equivalence the energy absorbed (in ergs/mole) is given as \[(h=6.62\times {{10}^{-27}}\]ergs, \[c=3\times {{10}^{10}}cm\text{ }{{s}^{-1}}\], \[{{N}_{A}}=6.02\times {{10}^{23}}mo{{l}^{-1}}\])

    A) \[\frac{1.956\times {{10}^{16}}}{\lambda }\]   

    B) \[\frac{1.19\times {{10}^{8}}}{\lambda }\]

    C) \[\frac{2.859\times {{10}^{5}}}{\lambda }\]     

    D) \[\frac{2.859\times {{10}^{16}}}{\lambda }\]

    Correct Answer: B

    Solution :

    [b] \[E=\frac{hc}{\lambda }\times {{N}_{A}}\] \[=\frac{6.62\times {{10}^{-27}}\times 3\times {{10}^{10}}\times 6.02\times {{10}^{23}}}{\lambda }\] \[=\frac{1.19\times {{10}^{8}}}{\lambda }\]


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