JEE Main & Advanced Chemistry Structure of Atom / परमाणु संरचना Question Bank Self Evaluation Test - Structure of Atom

  • question_answer
    When electronic transition occurs from higher energy state to lower energy state with energy difference equal to \[\Delta E\] electron volts, the wavelength of the line emitted is approximately equal to

    A) \[\frac{12395}{\Delta E}\times {{10}^{-10}}m\]

    B) \[\frac{12395}{\Delta E}\times {{10}^{10}}m\]

    C) \[\frac{12395}{\Delta E}\times {{10}^{-10}}cm\]

    D) \[\frac{12395}{\Delta E}\times {{10}^{10}}cm\]

    Correct Answer: A

    Solution :

    [a] \[\lambda =\frac{hc}{\Delta E}\] \[=\frac{6.62\times {{10}^{-34}}Js\times 3\times {{10}^{8}}m{{s}^{-1}}}{E\times 1.602\times {{10}^{-19}}J}\] \[=\frac{12395}{E}\times {{10}^{-10}}m\]


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