A) \[\frac{5}{36}R\]
B) \[\frac{9}{400}R\]
C) \[\frac{7}{6}R\]
D) \[\frac{3}{4}R\]
Correct Answer: A
Solution :
[a] \[\overline{v}=R{{Z}^{2}}\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{3}^{2}}} \right)\] \[=R\left( \frac{1}{4}-\frac{1}{9} \right)=\frac{5R}{36}\]
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