A) \[~1.37\times {{10}^{6}}\]
B) \[~1.26\times {{10}^{6}}\]
C) \[1.45\times {{10}^{7}}\]
D) \[~1.37 \times {{10}^{7}}\]
Correct Answer: A
Solution :
[a] \[\frac{1}{2}m{{v}^{2}}=hv-h{{v}_{0}}\] \[\Rightarrow \frac{1}{2}m{{v}^{2}}=h(v-{{v}_{0}})\] \[\Rightarrow v=\sqrt{\frac{2h}{m}(v-{{v}_{0}})}\] \[=\sqrt{\frac{2\times 6.6\times {{10}^{-34}}}{9.1\times {{10}^{-31}}}}(2\times {{10}^{15}}-7\times {{10}^{14}})\] \[=1.37\times {{10}^{6}}m{{s}^{1}}\]
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