A) \[\lambda =\frac{{{\lambda }_{1}}+{{\lambda }_{2}}}{{{\lambda }_{1}}{{\lambda }_{2}}}\]
B) \[\lambda =\frac{{{\lambda }_{1}}{{\lambda }_{2}}}{{{\lambda }_{1}}+{{\lambda }_{2}}}\]
C) \[\lambda =\frac{{{\lambda }_{1}}^{2}{{\lambda }_{2}}^{2}}{{{\lambda }_{1}}+{{\lambda }_{2}}}\]
D) \[\lambda =\frac{{{\lambda }_{1}}{{\lambda }_{2}}}{{{({{\lambda }_{1}}+{{\lambda }_{2}})}^{2}}}\]
Correct Answer: B
Solution :
[b] \[E={{E}_{1}}+{{E}_{2}};\] \[\frac{hc}{\lambda }=\frac{hc}{{{\lambda }_{1}}}+\frac{hc}{{{\lambda }_{2}}}\] \[\Rightarrow \frac{hc}{\lambda }=hc\left( \frac{{{\lambda }_{2}}+{{\lambda }_{1}}}{{{\lambda }_{1}}{{\lambda }_{2}}} \right);\,\,\lambda =\frac{{{\lambda }_{1}}{{\lambda }_{2}}}{{{\lambda }_{1}}+{{\lambda }_{2}}}\]
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