A) 3 units
B) 5 units
C) \[3\sqrt{3}\] Units
D) \[5\sqrt{2}\] units
Correct Answer: D
Solution :
[d] We have \[x-y=4\And 2x+3y+7=0\] On solving, we get \[x=1\,\,\And \,\,y=-\,3\] (These are coordinates of centre of the circle) \[\Rightarrow \,\,\,radius\,\,=\sqrt{{{(2-1)}^{2}}+{{(4+3)}^{2}}}=5\sqrt{2}\]
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