A) \[\frac{\pi }{3}\]
B) \[\frac{\pi }{2}\]
C) \[{{\tan }^{-1}}\left( \frac{{{1}^{2}}-{{m}^{2}}}{{{1}^{2}}+{{m}^{2}}} \right)\]
D) \[{{\tan }^{-1}}\left( \frac{2lm}{{{1}^{2}}+{{m}^{2}}} \right)\]
Correct Answer: B
Solution :
[b] The perpendicular distance between the parallel lines in pairs is same, hence the lines form a rhombus
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