A) Square
B) Circle
C) Straight line
D) Two intersecting line
Correct Answer: A
Solution :
[a] Let the two perpendicular lines be the coordinate axes and let the point be P(h, k). Then sum of the distances of P(h, k) from the coordinate axes is \[\left| h \right|+\left| k \right|.\] It is given that \[\left| h \right|+\left| k \right|=1.\] So, locus of (h, k) is \[\left| x \right|+\left| y \right|=1.\] this gives four lines \[x+y=1,x-y=1,-x+y=1,-x-y=1\] which enclose a square.
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