A) 2.018 L
B) 2.8 L
C) 3.5 L
D) 1.5 L
Correct Answer: A
Solution :
[a] \[{{V}_{1}}=2L,\] \[{{T}_{2}}=(26.1+273)K=299.1~K,\] \[{{V}_{2}}=?\] \[{{T}_{1}}=\left( 23.4+273 \right)K=296.4K\] From Charle's law, \[\frac{{{V}_{1}}}{{{T}_{1}}}=\frac{{{V}_{2}}}{{{T}_{2}}}\Rightarrow {{V}_{2}}=\frac{{{V}_{1}}{{T}_{2}}}{{{T}_{1}}}\] \[\Rightarrow {{V}_{2}}=\frac{2L\times 299.1K}{296.4K}=2L\times 1.009\] \[=2.018L\]
You need to login to perform this action.
You will be redirected in
3 sec
