A) 150 mm of Hg
B) 250 mm of Hg
C) 350 mm of Hg
D) 450 mm of Hg
Correct Answer: A
Solution :
[a] Given initial volume \[({{V}_{1}})=600\] c.c.; Initial pressure \[({{P}_{1}})=750mm\]of Hg and final volume \[({{V}_{2}})=500\] c.c. according to Boyle's law, \[{{\text{P}}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\] Or \[750\times 600={{P}_{2}}\times 500\] or \[{{P}_{2}}=\frac{750\times 600}{500}=900\,mm\]of Hg Therefore increase of pressure \[=\left( 900-750 \right)=150\text{ }mm\]of Hg
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