NEET Chemistry Solutions / विलयन Question Bank Self Evaluation Test - Solutions

  • question_answer
    A living cell contains a solution which is isotonic with 0.2 M glucose solution. What osmotic pressure develops when the cell is placed in  \[0.05M\text{ }BaC{{l}_{2}}\] solution at 300 K?

    A) 1.23 atm         

    B) 3.69 atm

    C) 6.15 atm         

    D) None of these

    Correct Answer: A

    Solution :

    [a] For non electrolyte solute (glucose) i = 1 For \[BaC{{l}_{2}}\rightleftharpoons B{{a}^{2+}}+2C{{l}^{-}}\] i= 3 (100% ionized) \[i=\left( number\text{ }of\text{ }ions\text{ }afierionization\times \alpha  \right)+\left( \text{1}-\alpha  \right)\] \[=\left( 3\times 1 \right)+\left( 1-1 \right)=3\] \[\pi =(i{{C}_{1}}-{{i}_{2}}{{C}_{2}})RT\] \[\Rightarrow \left( 1\times 0.2-3\times 0.05 \right)0.0821\times 300\] \[\Rightarrow 1.23\,atm\]


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