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NEET Chemistry Solutions / विलयन Question Bank Self Evaluation Test - Solutions

  • question_answer
    On mixing 3 g of non - volatile solute in 200 mL of water, its boiling point \[\left( 100{}^\circ  \right)\] becomes \[100.52{}^\circ C.\] If \[{{K}_{b}}\] for water is 0.6 K/m then molecular wt. of solute is:

    A) \[10.5g\,\,mo{{l}^{-1}}\]            

    B) \[12.6g\,\,mo{{l}^{-1}}\]

    C) \[15.7\,g\,\,mo{{l}^{-1}}\]               

    D) \[17.3\,g\,\,mo{{l}^{-1}}\]

    Correct Answer: D

    Solution :

    [d] \[\Delta {{T}_{b}}={{K}_{b}}\frac{w}{M}\times \frac{1000}{W}\] \[0.52=0.6\times \frac{3}{m}\times \frac{1000}{200}(W=200\times 1)\] \[m=\frac{1.8\times 5}{0.52}=17.3g\,mo{{l}^{-1}}\]


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