NEET Chemistry Solutions / विलयन Question Bank Self Evaluation Test - Solutions

  • question_answer
    The osmotic pressure (at \[27{}^\circ C\]) of an aqueous solution (200mL) containing 6g of a protein is \[2\times {{10}^{-3}}\] atm. If R= 0.080 L atm\[mo{{l}^{-1}}{{K}^{-1}}\], the molecular weight of protein is

    A) \[7.2\times {{10}^{5}}\]          

    B) \[3.6\times {{10}^{5}}\]

    C) \[1.8\times {{10}^{5}}\]         

    D) \[1.0\times {{10}^{5}}\]

    Correct Answer: B

    Solution :

    [b] Using the relation, \[M=\frac{w.R.T}{\pi V},\] We get \[M=\frac{6\times 0.080\times 300}{2\times {{10}^{-3}}\times 0.2}=3.6\times {{10}^{5}}\]


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