NEET Chemistry Solutions / विलयन Question Bank Self Evaluation Test - Solutions

  • question_answer
    At 760 torr pressure and \[20{}^\circ C\]temperature, 1 L of water dissolves 0.04 gm of pure oxygen or 0.02 gm of pure nitrogen. Assuming that dry air is composed of 20% oxygen and 80% nitrogen (by volume), the masses (in g/L) of oxygen and nitrogen dissolved by 1 L of water at \[20{}^\circ C\]exposed to air at a total pressure of 760 torr are respectively: 

    A) 0.008, 0.016                 

    B) 0.016, 0.008

    C) 0.16, 0.08                     

    D) 0.04, 0.02

    Correct Answer: A

    Solution :

    [a] Mass of oxygen \[=\frac{20}{100}\times 0.04=0.008g/L\] Mass of nitrogen \[=\frac{80}{100}\times 0.02=0.016g/L\]


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