A) \[[Pt{{(N{{H}_{3}})}_{6}}]C{{l}_{4}}\]
B) \[[Pt{{(N{{H}_{3}})}_{5}}Cl]C{{l}_{3}}\]
C) \[[Pt{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]C{{l}_{2}}\]
D) \[[Pt{{(N{{H}_{3}})}_{3}}C{{l}_{3}}]Cl\]
Correct Answer: A
Solution :
[a] \[\left[ Pt{{\left( N{{H}_{3}} \right)}_{6}} \right]C{{l}_{4}}\to {{\left[ Pt{{\left( N{{H}_{3}} \right)}_{6}} \right]}^{4+}}+4C{{l}^{-}};\] \[i=1+4=5\](maximum)
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