A) \[[Cr{{\left( {{H}_{2}}O \right)}_{3}}C{{l}_{3}}].3{{H}_{2}}O\]
B) \[[Cr{{\left( {{H}_{2}}O \right)}_{4}}C{{l}_{4}}]Cl.2{{H}_{2}}O\]
C) \[[Cr{{\left( {{H}_{2}}O \right)}_{5}}Cl]C{{l}_{2}}.{{H}_{2}}O\]
D) \[[Cr{{\left( {{H}_{2}}O \right)}_{6}}]C{{l}_{3}}\]
Correct Answer: C
Solution :
[c] \[i=\frac{5.58}{1.86}=3;\] \[\left[ Cr{{\left( {{H}_{2}}O \right)}_{5}}Cl \right]C{{l}_{2}}.{{H}_{2}}O\xrightarrow{{}}\] \[{{[Cr{{({{H}_{2}}O)}_{5}}Cl]}^{2+}}+2C{{l}^{-}}\]You need to login to perform this action.
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