A) \[{{\pi }_{1}}>{{\pi }_{4}}>{{\pi }_{2}}>{{\pi }_{3}}\]
B) \[{{\pi }_{1}}>{{\pi }_{4}}>{{\pi }_{2}}>{{\pi }_{3}}\]
C) \[{{\pi }_{4}}>{{\pi }_{1}}>{{\pi }_{2}}>{{\pi }_{3}}\]
D) \[{{\pi }_{4}}>{{\pi }_{1}}>{{\pi }_{3}}>{{\pi }_{2}}\]
Correct Answer: C
Solution :
[c] Moles of urea \[=\frac{5}{60};\] moles of fructose \[=\frac{5}{180};\] \[{{C}_{urea}}=\frac{0.08\times 1000}{100}\Rightarrow 0.833\] moles of sucrose \[=\frac{5}{342};\] \[{{C}_{sucrose}}=0.0146\times \frac{1000}{100}=0.146\] moles of \[KCl\] (effective) \[=2\times \frac{5}{74.5}=\frac{5}{37.25};\frac{0.134\times 1000}{100}=1.34\] \[\pi \propto C\] this order is \[{{\pi }_{4}}>{{\pi }_{1}}>{{\pi }_{2}}>{{\pi }_{3}}\]You need to login to perform this action.
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