NEET Chemistry Solutions / विलयन Question Bank Self Evaluation Test - Solutions

  • question_answer
    A solution containing 1.8 g of a compound (empirical formula \[C{{H}_{2}}O\]) in 40 g of water is observed to freeze at \[-0.465{}^\circ C\]. The molecular formula of the compound is (\[{{K}_{f}}\] of water \[=1.86kg\text{ }K\text{ }mo{{l}^{-1}}\])

    A) \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\]                  

    B) \[{{C}_{3}}{{H}_{6}}{{O}_{3}}\]

    C) \[{{C}_{4}}{{H}_{8}}{{O}_{4}}\]                  

    D) \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\]

    Correct Answer: D

    Solution :

    [d] \[\Delta {{T}_{f}}={{K}_{f}}\times m\] \[M=\frac{1000\times {{K}_{f}}\times {{w}_{2}}\left( solute \right)}{\Delta {{T}_{f}}\times {{w}_{1}}\left( solvent \right)}\]                 \[=\frac{1000\times 1.86\times 1.8}{0.465\times 40}\Rightarrow M=180\] Molecular formula = \[{{(empirical\text{ }formulae)}_{n}}\] \[n=\frac{Molecular\text{ }mass}{Empirical\text{ }formula\text{ }mass}=\frac{180g}{30}=6\] Molecular formula \[={{(C{{H}_{2}}O)}_{6}}={{C}_{6}}{{H}_{12}}{{O}_{6}}\]


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