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NEET Chemistry Solutions / विलयन Question Bank Self Evaluation Test - Solutions

  • question_answer
    200 mL of an aqueous solution of a protein contains its 1.26 g. The osmotic pressure of this solution at 300 K is found to be \[2.57\times {{10}^{-3}}\] bar. The molar mass of protein will be (R = 0.083 L bar \[mo{{l}^{-1}}{{K}^{-1}}\])

    A) \[51022g\text{ }mo{{l}^{-1}}\]            

    B) \[122044g\text{ }mo{{l}^{-1}}\]

    C) \[31011g\,mo{{l}^{-1}}\]

    D) \[61038g\,mo{{l}^{-1}}\]

    Correct Answer: D

    Solution :

    [d] Osmotic pressure \[\left( \pi  \right)=CRT\]  \[(\pi )=\frac{wt\times 1000}{Molecular\text{ }mass\times V}RT\] \[=2.57\times {{10}^{-3}}=\frac{26\times 1000}{Mol.mass\times 200}\times 0.083\times 300\] Molecular mass = 61038 g


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