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NEET Chemistry Solutions / विलयन Question Bank Self Evaluation Test - Solutions

  • question_answer
    A 0.001 molal solution of\[[Pt{{(N{{H}_{3}})}_{4}}C{{l}_{4}}]\] in water had a freezing point depression of\[0.0054{}^\circ C\]. If \[{{K}_{f}}\] for water is 1.80, the correct formulation for the above molecule is

    A) \[[Pt{{(N{{H}_{3}})}_{4}}C{{l}_{3}}]Cl\]       

    B) \[[Pt{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]C{{l}_{2}}\]

    C) \[[Pt{{(N{{H}_{3}})}_{4}}Cl]C{{l}_{3}}\]       

    D) \[[Pt{{(N{{H}_{3}})}_{4}}C{{l}_{4}}]\]

    Correct Answer: B

    Solution :

    [b] \[\Delta {{T}_{f}}=i.{{K}_{f}}.m;\text{ }0.0054=i\times 1.8\times 0.001\] \[i=3\] so it is \[[Pt{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]C{{l}_{2}}.\]


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