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NEET Chemistry Solutions / विलयन Question Bank Self Evaluation Test - Solutions

  • question_answer
    Vapour pressure of pure benzene is 119 torr and that of toluene is 37.0 torr at the same temperature. Mole fraction of toluene in vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene 0.50, will be:

    A) 0.137               

    B) 0.237

    C) 0.435               

    D) 0.205

    Correct Answer: B

    Solution :

    [b] \[{{P}_{A}}=P_{A}^{{}^\circ }\times {{x}_{A}}\]= total pressure \[\times {{y}_{A}}\] \[{{P}_{B}}=P_{B}^{{}^\circ }\times {{x}_{B}}\] pressure \[\times {{y}_{B}}\] where x and y represents mole fraction in liquid and vapour phase respectively. \[\frac{P_{B}^{{}^\circ }{{x}_{B}}}{P_{A}^{{}^\circ }{{x}_{A}}}=\frac{{{y}_{B}}}{{{y}_{A}}};\frac{P_{B}^{{}^\circ }(1-{{x}_{A}})}{P_{A}^{{}^\circ }{{x}_{A}}}=\frac{1-{{y}_{A}}}{{{y}_{A}}}\] on putting values \[\frac{119(1-0.50)}{37\times 0.50}=\frac{1-{{y}_{A}}}{{{y}_{A}}}\] on solving \[{{y}_{A}}=0.237\]


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