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NEET Chemistry Solutions / विलयन Question Bank Self Evaluation Test - Solutions

  • question_answer
    The vapour pressure of pure benzene and toluene at a particular temperature are 100 mm and 50 mm respectively. Then the mole fraction of benzene in vapour phase in contact with equimolar solution of benzene and toluene is

    A) 0.67                 

    B) 0.75  

    C) 0.33                 

    D) 0.50

    Correct Answer: A

    Solution :

    [a] Total vapour pressure = vapour pressure of pure benzene + vapour pressure of \[=100+50=150\text{ }mm\] We know, \[P_{{{C}_{6}}{{H}_{6}}}^{{}^\circ }=P\times {{X}_{C6H6}}\] \[100=150\times {{X}_{C6H6}}\] \[{{X}_{C6H6}}=\frac{100}{150}=0.67\]


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