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NEET Chemistry Solutions / विलयन Question Bank Self Evaluation Test - Solutions

  • question_answer
    At a particular temperature, the vapour pressures of two liquids A and B are respectively 120 and 180 mm of mercury If 2 moles of A and 3 moles of B are mixed to form an ideal solution, the vapour pressure of the solution at the same temperature will be (in mm of mercury)

    A) 156                  

    B) 145  

    C) 150                  

    D) 108

    Correct Answer: A

    Solution :

    [a] Vapour pressure of solution \[={{P}_{A}}+{{P}_{B}}\] \[=P_{A}^{{}^\circ }{{X}_{A}}+P_{B}^{{}^\circ }{{X}_{B}}=\frac{120\times 2}{5}+\frac{180\times 3}{5}\] =156 mmHg


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