A) 27 mL
B) 54 mL
C) 33.75 mL
D) 67.50 mL
Correct Answer: B
Solution :
[b] \[{{V}_{dissolved}}=K{{P}_{H2}}\] \[{{P}_{H2}}\] in the mixture\[={{X}_{H2}}P=\frac{80\times 1425}{100}=1140\] \[torr=\frac{1140}{760}=1.5atm\] Hence, \[{{V}_{dissolved}}\] in 2L of water \[=2\times K\times {{P}_{H2}}\] \[=2\times 18\times 1.5=54\text{ }mL\]
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