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NEET Chemistry Solutions / विलयन Question Bank Self Evaluation Test - Solutions

  • question_answer
    Lowering of vapour pressure of 1.00 m solution of a non-volatile solute in a hypothetical solvent of molar mass 40 g at its normal boiling point, is:

    A) 29.23 torr                  

    B) 30.4 torr

    C) 35.00 torr         

    D) 40.00 torr

    Correct Answer: A

    Solution :

    [a] \[P_{solvent}^{{}^\circ }=760\,torr\](at the b. pt); \[{{n}_{solute}}=1\] \[{{n}_{solvent}}=\frac{1000}{40}=25;\] \[\Delta P=760\times {{X}_{solute}}=\frac{760}{26}\,torr=29.23\,torr\]


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