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NEET Chemistry Solutions / विलयन Question Bank Self Evaluation Test - Solutions

  • question_answer
    The vapour pressure (at the standard boiling point of water) of an aqueous solution containing 28% by mass of a non-volatile normal solute (molecular mass = 28) will be

    A) 152 torr            

    B) 608 torr

    C) 760 torr            

    D) 547 torr

    Correct Answer: B

    Solution :

    [b] Moles of solute \[=\frac{28}{28}=1;\] moles of water \[=\frac{100-28}{18}=4\] V.P. of solution                 \[=P_{{{H}_{2}}O}^{{}^\circ }\times {{X}_{{{H}_{2}}O}}=760\times \frac{4}{5}=608\,torr\]


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