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NEET Chemistry Solutions / विलयन Question Bank Self Evaluation Test - Solutions

  • question_answer
    Vapour pressure (in torr) of an ideal solution of two liquids A and B is given by: \[P=52{{X}_{A}}+114\] where \[{{X}_{A}}\] is the mole fraction of A in the mixture. The vapour pressure (in torr) of equimolar mixture of the two liquids will be: 

    A) 166                  

    B) 83    

    C) 140                  

    D) 280

    Correct Answer: C

    Solution :

    [c] Total V.P., \[P=P_{A}^{0}{{X}_{A}}+P_{B}^{0}{{X}_{B}}=P_{A}^{0}{{X}_{A}}+P_{B}^{0}(1-{{X}_{A}})\] \[=\left( P_{A}^{0}-P_{B}^{0} \right){{X}_{A}}+P_{B}^{0}\] Thus, \[{{P}_{B}}{}^\circ =114\,torr;\,\,P_{A}^{0}-P_{B}^{0}=52\] or \[P_{A}^{0}=166\text{ }torr\] Hence \[P=166\times \frac{1}{2}+114\times \frac{1}{2}=140\text{ }torr\]


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