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NEET Chemistry Solutions / विलयन Question Bank Self Evaluation Test - Solutions

  • question_answer
    The vapour pressure of a solution of the liquids A (\[P{}^\circ =80\] mm Hg and \[{{x}_{A}}=0.4\]) and B (\[P{}^\circ =120\] mm Hg and \[{{X}_{B}}=0.6\]) is found to be \[100mm\]Hg. It shows that the solution exhibits

    A) positive deviation from ideal behaviour

    B) negative deviation from ideal behaviour

    C) ideal behaviour

    D) positive deviation for lower cone. and negative for higher cone.

    Correct Answer: B

    Solution :

    [b] \[{{P}_{total}}=P_{A}^{0}\times {{X}_{A}}+P_{B}^{0}\times {{X}_{B}}\] \[=80.0\times 0.4+120.0\times 0.6=104\text{ }mm\] Hg The observed \[{{P}_{total}}\] is 100 mm Hg which is less than 104 mm Hg. Hence the solution shows negative deviation.


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