NEET Chemistry Solutions / विलयन Question Bank Self Evaluation Test - Solutions

  • question_answer
    Vapour pressure of chloroform \[(CHC{{l}_{3}})\] and dichloromethane \[(C{{H}_{2}}C{{l}_{2}})\] at \[25{}^\circ \]C are 200 mm Hg and 41.5 mm Hg respectively. Vapour pressure of the solution obtained by mixing 25.5 g of \[CHC{{l}_{3}}\] and 40 g of\[C{{H}_{2}}C{{l}_{2}}\] at the same temperature will be: (Molecular mass of \[CHC{{l}_{3}}=119.5u\] and molecular mass of \[C{{H}_{2}}C{{l}_{2}}=85u\]).

    A) 90.92 mm Hg                

    B) 115.0 mm Hg

    C) 147.9 mm Hg                

    D) 285.5 mm Hg

    Correct Answer: A

    Solution :

    [a] \[^{n}CHC{{l}_{3}}=\frac{25.5}{119.5}=0.213\] \[^{n}C{{H}_{2}}C{{l}_{2}}=\frac{40}{85}=0.47\] \[{{P}_{T}}=P_{A}^{0}{{X}_{A}}+P_{B}^{0}{{X}_{B}}\] \[=200\times \frac{0.213}{0.683}+41.5\times \frac{0.47}{0.683}\] \[=62.37+28.55=90.92\]


You need to login to perform this action.
You will be redirected in 3 sec spinner