A) 0
B) 1
C) 4
D) 16
Correct Answer: D
Solution :
[d]Since, A is void set therefore the number of elements in power set of A is 1. \[\therefore P\{P(A)\}={{2}^{1}}=2\] because if set A has n elements then \[P(A)\] has \[{{2}^{n}}\] elements. \[\Rightarrow P{{\{P\{P(A)\}=2\}}^{2}}=4\] \[\Rightarrow P\{P\{P\{P(A)\}\}\}={{2}^{4}}=16\]
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