A) 16
B) 6
C) 8
D) 20
Correct Answer: A
Solution :
[a]Given \[n(N)=12,n(P)=16,n(H)=18,n(N\cup P\cup H)=30\] From, \[n(N\cup P\cup H)=n(N)+n(P)+n(P)+n(H)-n(N\cap P)\]\[-n(P\cap H)-n(N\cap H)+n(N\cap P\cap H)\] \[\therefore n(N\cap P)+n(P\cap H)+n(N\cap H)=16\] Now, number of pupils taking two subjects \[=n(N\cap P)+n(P\cap H)+n(N\cap H)-3n(N\cap P\cap H)\] \[=16-0=16\]You need to login to perform this action.
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