1. \[A-(B-C)=(A-B)\cup C\] |
2. \[A-(B\cup C)=(A-B)-C\] |
A) 1 only
B) 2 only
C) Both 1 and 2
D) neither 1 nor 2
Correct Answer: B
Solution :
[b]Let there be three non-empty, non-overlapping sets; inside a universal set U. This creates 8 regions marked as: a, b, c, d, e, f, g, h. Statement1: \[A-(B-C)=(A-B)\cup C\] LHS represent region a, RHS represent a, d, g. Hence, this is not correct. Statement2: \[A-(B\cup C)=(A-B)-C\] LHS represents, region ?a? RHS also represent a. Hence, only statement 2 is correct.You need to login to perform this action.
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