A) \[{{x}^{2}}+4x-1=0\]
B)
C) \[{{x}^{2}}+4x+1=0\]
D) \[{{x}^{2}}-4x+1=0\]
Correct Answer: D
Solution :
[d] \[a=\frac{1}{1-\left( \sqrt{3}-1 \right)}=\frac{1}{2-\sqrt{3}}=2+\sqrt{3}\] and \[ab=1\Rightarrow b=2-\sqrt{3}\] so, a and b are roots of \[{{x}^{2}}-4x+1=0\]
You need to login to perform this action.
You will be redirected in
3 sec
