JEE Main & Advanced Mathematics Sequence & Series Question Bank Self Evaluation Test - Sequences and Series

  • question_answer
    For \[-\pi <x<\pi ,\] the values of x which satisfy the relation \[{{11}^{1+\left| \cos \,x \right|+co{{s}^{2}}x+\left| {{\cos }^{3}}x \right|+...upt{{o}^{\infty }}}}=121\] are given by

    A) \[\pm \frac{\pi }{3},\pm \frac{2\pi }{3}\]

    B) \[\frac{\pi }{3},\frac{2\pi }{4}\]

    C) \[\frac{\pi }{4},\frac{3\pi }{4}\]

    D) None of these

    Correct Answer: A

    Solution :

    [a] Since, \[0<x<\pi ,-1<\cos x<1\Rightarrow 0\le |\cos x|<1\]. We can write the given expression as \[{{11}^{1/(1-|\cos x|)}}=121\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\frac{1}{1-\left| \cos x \right|}=2\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,1-\left| \cos x \right|=\frac{1}{2}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\left| \cos x \right|=\frac{1}{2}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\cos x=\pm \frac{1}{2}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,x=\pm \frac{\pi }{3},\,\,\pm \frac{2\pi }{3}\]


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