JEE Main & Advanced Mathematics Sequence & Series Question Bank Self Evaluation Test - Sequences and Series

  • question_answer
    What is the sum of the series 0.5 + 0.55 + 0.555 +... to n terms?

    A) \[\frac{5}{9}\left[ n-\frac{2}{9}\left( 1-\frac{1}{{{10}^{n}}} \right) \right]\]

    B) \[\frac{1}{9}\left[ 5-\frac{2}{9}\left( 1-\frac{1}{{{10}^{n}}} \right) \right]\]

    C) \[\frac{1}{9}\left[ n-\frac{5}{9}\left( 1-\frac{1}{{{10}^{n}}} \right) \right]\]

    D) \[\frac{5}{9}\left[ n-\frac{1}{9}\left( 1-\frac{1}{{{10}^{n}}} \right) \right]\]

    Correct Answer: D

    Solution :

    [d] Given \[0.5+0.55+0.555+.....\text{ }to\,\,n\]
    \[=5[0.1+0.11+0.111+.......to\,\,n\,\,terms]\]
    \[=\frac{5}{9}[0.9+0.99+0.999+.......to\,\,n\,\,terms]\]
    \[=\frac{5}{9}\left[ \frac{9}{10}+\frac{99}{100}+\frac{999}{1000}+......\,\,to\,n\,terms \right]\]
    \[=\frac{5}{9}\left[ \begin{align}   & \left( 1-\frac{1}{10} \right)+\left( 1-\frac{1}{100} \right)+\left( 1-\frac{1}{1000} \right)+.... \\  & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,to\,\,n\,\,terms \\ \end{align} \right]\]
    \[=\frac{5}{9}\left[ \begin{align}   & \left( 1-\frac{1}{10} \right)+\left( 1-\frac{1}{{{10}^{2}}} \right)+\left( 1-\frac{1}{{{10}^{3}}} \right)+.... \\  & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left( 1-\frac{1}{{{10}^{n}}} \right) \\ \end{align} \right]\]
    \[=\frac{5}{9}\left[ n-\left( \frac{1}{10}+\frac{1}{{{10}^{2}}}+....\frac{1}{{{10}^{n}}} \right) \right]\]
    \[=\frac{5}{9}\left[ n-\frac{1}{10}\frac{\left\{ 1-{{\left( \frac{1}{10} \right)}^{n}} \right\}}{\left( 1-\frac{1}{10} \right)} \right]\]
    \[=\frac{5}{9}\left[ n-\frac{1}{9}\left( 1-\frac{1}{{{10}^{n}}} \right) \right]\]


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