JEE Main & Advanced Mathematics Functions Question Bank Self Evaluation Test - Relations and Functions-I

  • question_answer
    If \[{{\log }_{1/2}}\left( {{x}^{2}}-5x+7 \right)>0,\] then exhaustive range of values of x is

    A) \[(-\infty ,2)\cup (3,\infty )\]

    B) \[(2,3)\]

    C) \[(-\infty ,1)\cup (1,2)\cup (2,\infty )\]

    D) None of these

    Correct Answer: B

    Solution :

    [b] \[f(x)=lo{{g}_{1/2}}({{x}^{2}}-5x+7)>0\Rightarrow {{x}^{2}}-5x+7>0\] \[{{x}^{2}}-5x+7<1,x\in R\Rightarrow {{x}^{2}}-5x+6<0\Rightarrow x\in (2,3)\]


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