A) \[\{1,-1\}\]
B) \[\{1\}\]
C) \[\{-1\}\]
D) None of these
Correct Answer: B
Solution :
[b] \[{{x}^{2}}-2x+3={{(x-1)}^{2}}+1>0\,\forall \,x\in R\] Or \[f(x)=sgn({{x}^{2}}-2x+3)=1.\] hence, the range is {1}.
You need to login to perform this action.
You will be redirected in
3 sec
