JEE Main & Advanced Mathematics Functions Question Bank Self Evaluation Test - Relations and Functions-I

  • question_answer
    A relation R is defined over the set of nonnegative integers as \[xRy\Rightarrow {{x}^{2}}+{{y}^{2}}=36\] what is R?

    A) \[\{(0,6)\}\]

    B) \[\{(6,0)(\sqrt{11},5),(3,3,\sqrt{3})\]

    C) \[\{(6,0)(0,6)\}\]

    D) \[(\sqrt{11},5),(2,4\sqrt{2}),(5\sqrt{11}),(4\sqrt{2}2)\}\]

    Correct Answer: C

    Solution :

    [b] R is defined over the set of non-negative integers, \[{{x}^{2}}+{{y}^{2}}=36\] \[\Rightarrow y=\sqrt{36-{{x}^{2}}}=\sqrt{(6-x)(6+x)},x=0\]or 6 for x = 0, y = 6 and for x = 6, y = 0 So, y is 6 or 0 so, \[R=\{(6,0),(0,6)\}\]


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