JEE Main & Advanced Mathematics Functions Question Bank Self Evaluation Test - Relations and Functions-I

  • question_answer
    The domain of \[F(x)=\frac{{{\log }_{2}}(x+3)}{{{x}^{2}}+3x+2}\] is

    A) \[R-\{-1,-2\}\]

    B)        \[(-2,\infty )\]

    C) \[R-\{-1,-2-3\}\]

    D)        \[(-3,\infty )-\{-1,-2\}\]

    Correct Answer: D

    Solution :

    [d] We have , \[F(x)=\frac{{{\log }_{2}}(x+3)}{{{x}^{2}}+3x+2}\] \[\therefore \,\,\,\,F(x)\] is defined if \[x+3>0\] and \[{{x}^{2}}+3x+2\ne 0\] \[\Rightarrow F(x)\] is defined if \[x>-3\] and \[x\ne -1,-2\] \[\Rightarrow \] Domain of \[F(x)=(-3,\infty )-\{-1,\,\,-2\}\]


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