A) \[{{x}^{2}}-5x-6\]
B) \[{{x}^{2}}+5x-6\]
C) \[{{x}^{2}}+5x+6\]
D) \[{{x}^{2}}-5x+6\]
Correct Answer: D
Solution :
[d] Given function is: \[f(x+1)={{x}^{2}}-3x+2\] This function is valid for all real values of x. so, putting x - 1 in place. Of x, we get \[f(x)=f(x-1+1)\Rightarrow f(x)={{(x-1)}^{2}}-3(x-1)+2\] \[\Rightarrow f(x)={{x}^{2}}-2x+1-3x+3+2\] \[\Rightarrow f(x)={{x}^{2}}-5x+6\]
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