A) \[x-\left[ \frac{x}{2} \right]\]
B) \[-x-2\]
C) \[x-2\]
D) \[\frac{1}{x+\left[ \frac{x}{2} \right]}\]
Correct Answer: C
Solution :
[c] Since \[f:(4,6)\to (6,8)\Rightarrow f(x)=x+2\] \[\therefore {{f}^{-1}}(x)=x-2\]
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